mols C = 26.7/44 = ?(not 1 mol)
mols H = 9.10 x (2/18) = ? (not 2 mols)
The 8.20 is extraneous information unless there is another part of the problem.
Complete combustion of 8.30 g of a hydrocarbon produced 26.7 g of CO2 and 9.10 g of H2O. What is the empirical formula for the hydrocarbon?
My Work:
First I tried to find the Amount of C and H in the product... Which I got 1 Mole of Carbon and 2 moles of Hydrogen... Now I'm just stuck on finding CH (hydrocarbon) when I know I have 8.20g of CH.
1 answer