Complete and balance these half-equations. Express as net ionic eqn.

1.) Cr2O7(2−) → Cr(3+) (acidic solution)
So far, I have: Cr2O7(2−) + 14H + 6e(-) →2Cr(3+) + 7H20

2.) C2O4(2−) → CO2 (acidic solution)
Not sure how to do this one.

Thank you.

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