Balance ionic equations in acidic medium,

Cr2O7^2- + H^+ + C2O4^2- --> Cr^3+ + CO2

1 answer

Cr2O7^2- + 14H^+ + 3C2O4^2- --> 2Cr^3+ + 6CO2 + 7H2O
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To be balanced you must have
1. number of atoms of each element on each side must be the same.
2. the charge must balance.
3. electrons lost by oxidation must = electrons gained by reduction.