Compare the areas of two rectangular regions if the length of one rectangular region is double that of the other, and the width is triple that of the other. (Use an algebraic formula.)

Answer 1

l = length of original rectangle
w = width of original rectangle

2l = length of new rectangle
3w = width of new rectangle

Area of first rectangle is lw
Area of second rectangle is (2l)(3w) = 6 lw

Second rectangle has an area 6 times the first one.