Compare Proportional Relationships Practice

Question

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5 of 55 of 5 Items

Question
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Option A and Option B are available for passes to ride public transportation. Option A is represented by the equation y=4.25x
. Option B is displayed in the graph. Which option is cheaper per day? Enter 1 for Option A. Enter 2 for Option B.

(1 point)
is cheaper per day.
Remaining A

Answer 1

To determine which option is cheaper per day, we need to compare the two options based on their equations and the graph for Option B.

1. Option A: The equation is \( y = 4.25x \), where \( y \) represents the total cost and \( x \) is the number of days.

   • If we plug in \( x = 1 \) (for one day), the cost is: \[ y = 4.25 \times 1 = 4.25 \]
   • For two days (\( x = 2 \)): \[ y = 4.25 \times 2 = 8.50 \]

2. Option B: We need to look at the graph to interpret the cost based on the number of days.

   • Without the visual context of the graph, I will assume that Option B follows a linear relationship as well. If you provide the specific details or coordinates for Option B's graph, I can calculate specific daily costs.

3. Comparison: Compare the daily costs for the same value of \( x \) (days) for both options. If Option A's total cost is less than Option B's for the same days, then Option A is cheaper, and vice versa.

Since I don't have the specific numbers from Option B's graph, I cannot definitively say which one is cheaper without that information. If you reference the graph and determine Option B's costs, you can fill in your answer accordingly:

• If \( y \) of Option A is less than \( y \) of Option B, then Option A (1) is cheaper.
• If \( y \) of Option B is less than \( y \) of Option A, then Option B (2) is cheaper.

Please check the graph and calculate accordingly.