Asked by kimie
There is proportional relationship between your distance from a thunderstorm and the time from when you see lightning and hear thunder. If there are 9 seconds between lightning and thunder, the storm is about 3 kilometers away. If you double the amount of time between lightning and thunder, do you think the distance in kilometers also doubles? Justify your reasoning.
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Answers
Answered by
Steve
since the relationship is proportional, the distance d and the time t are related by
d = kt
where k is a constant.
So, if you double the time, you have
k(2t) = 2(kt) = 2d
so, the distance also doubles.
Or, you can think of it like this.
d/t = k, a constant
If you now have 2t, you need 2d so that
2d/2t = (2/2)(d/t) is still k.
d = kt
where k is a constant.
So, if you double the time, you have
k(2t) = 2(kt) = 2d
so, the distance also doubles.
Or, you can think of it like this.
d/t = k, a constant
If you now have 2t, you need 2d so that
2d/2t = (2/2)(d/t) is still k.
Answered by
NO NAME
d=kt
k(2*t)=2(k*t)=2*d
3(2*9)=2(3*9)=2*d
54=54=2*d
d/t=k
2*d/2*t=(2/2)(d/t)
2*d/2(9)
54/18
=3 kilometers or k
k(2*t)=2(k*t)=2*d
3(2*9)=2(3*9)=2*d
54=54=2*d
d/t=k
2*d/2*t=(2/2)(d/t)
2*d/2(9)
54/18
=3 kilometers or k
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