molarity=moles/volume
assume 1.000 liters, 1190grams.
of that, .38*1190 = mass HCL
moles HCl= massHCl/38
figure molarity from that. I get about 12M
Now, knowing the original molarity, say it is 12 (you better work that out),
then you are trying to dilute it 12/.1 or 120 times, which means one part original, 119 parts water.
Whatis 1 Part? 1000cc/120=8.333 cc
commercially available concentrated H CL contains 38% H CL by mass
(a) what is the molarity of this solution if the density in 1.19gm/l
(b) what volume of concentrated HCL is required to make 1l of 0.1M HCL?
1 answer
3 answers