grams HCl in 1000 mL is
1.18 g/mL x 1000 mL x 0.37 = approx 437 g but that's just an estimate.
Then mols in that 1 L = grams/molar mass = approx 437/36.5 = about 12 M, another estimate.
Since that is mols/L that is M.
b.
g HCl = mols HCl x molar mass HCl so g HCl = 0.315 x 36.5 = approx 11.5 g. Substitute the 11.5 g HCl into the formula below (the same I used above for grams HCl--but then in 1000 mL) and solve for mL. I get about 26 mL.
density x vol x % = grams
Mass
commercially available concentrated Hydrochloric acid is 37.0% w/w Hcl.its density is 1.18g/ml.using this information calculate (a)the molarity of concentrated Hcl,and (b)the mass and volume (in ml)of solution containing 0.315 mol of Hcl?
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