2MnO4^- + 5H2O2 + 6H^+ ==>2Mn^2+ + 5O2 + 8H2O
Check that equation.
mols MnO4^- = M x L = approx 0.0005 but you must redo this to obtain a better answer.
Using the coefficients in the balanced equation, convert mols MnO4^- to mols H2O2. That will be approx 0.0005 x (5 mols H2O2/2 mols MnO4^-) = ??
Then M H2O2 = mols H2O2/L H2O2 = ??mols H2O2/0.025L = ?
Then multiply the final number you have by 150 to find the concn of the original commercial H2O2.
Post your work if you get stuck.
Commercial aqueous hydrogen peroxide was diluted 150 times. 25cm3 of the sample solution was titrated with 0.02molar KMnO4 and 26.3cm3 was required to reach the end point. Calculate the molar concentration of hydrogen peroxide
1 answer