You posted this earlier and this repost is just as confusing as the first one.
from your f(4) = 1/2 * 4 + 1
I could guess that your function was f(x) = (1/2)x + 1
so I can change the slope to -1/2 which is -1 ≤ m ≤ 0, but now what ?
linear functions, unless they are vertical or horizontal, do not approach
any constant value.
Come up with a new linear function that has a slope that falls in the range -1<m<0. Choose two different initial values. For this new linear function,
what happens to the function’s values after many iterations? Are the
function’s values getting close to a particular number in each case?
(The linear function before this was f(4)=1/2*4+1=3 idk if this will help)
Can someone please explain what they are asking or give me an example of what they're asking for?
2 answers
This actually helped me out a lot! Thank you so much