Cole is incorrect. The mistake is in Step 2.
Step 1: h(x)= (x^2−6x+ )+7
Step 2: h(x)=(x^2−6x+ 9 )+7 - 9
Step 3: h(x)=(x−3 )^2-2
Therefore, the correct vertex is (3, -2).
Cole rewrote a quadratic function in vertex form.
h(x)= x^2−6x+7
Step 1: h(x)= (x^2−6x+ )+7
Step 2: h(x)=(x^2−6x+ 9 )+7 −9
Step 3: h(x)=(x−3 )^2+2
Cole said that the vertex is (3, 2). Is Cole correct? If not, identify the step in which Cole made the mistake and correct his work. step by step
the correct vertex is 3,-2
3 answers
so what would be the corrrect steps
Apologies for the confusion in the previous response. Here are the corrected steps to rewrite the quadratic function h(x) = x^2 - 6x + 7 in vertex form:
Step 1: h(x) = x^2 - 6x + 7
Step 2: h(x) = (x^2 - 6x + 9) - 9 + 7
Step 3: h(x) = (x - 3)^2 - 2
Therefore, the correct vertex is (3, -2).
Step 1: h(x) = x^2 - 6x + 7
Step 2: h(x) = (x^2 - 6x + 9) - 9 + 7
Step 3: h(x) = (x - 3)^2 - 2
Therefore, the correct vertex is (3, -2).