To determine which option represents a viable solution for the number of robotics kits (y) and chemistry sets (x) Cindy can buy with her $50, we can set up the equation based on her earnings:
The total cost for robotics kits and chemistry sets can be represented by the equation: \[ 10y + 8x = 50 \]
Now let's check each option to see if it satisfies this equation:
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Option (3, 2.6): \[ 10(3) + 8(2.6) = 30 + 20.8 = 50.8 \quad \text{(Not valid, exceeds $50)} \]
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Option (5, 1): \[ 10(5) + 8(1) = 50 + 8 = 58 \quad \text{(Not valid, exceeds $50)} \]
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Option (0, 5): \[ 10(0) + 8(5) = 0 + 40 = 40 \quad \text{(Valid, under $50)} \]
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Option (-5, 9): \[ 10(-5) + 8(9) = -50 + 72 = 22 \quad \text{(Not valid, negative robotics kits)} \]
The only viable solution from the given options is:
- (0, 5)
This means Cindy can buy 0 robotics kits and 5 chemistry sets, spending a total of $40.