Let's assume Cindy buys "y" robotics kits and "x" chemistry sets.
The cost of each robotics kit is $10.00, so the total cost of the robotics kits is y * $10.
The cost of each chemistry set is $8.00, so the total cost of the chemistry sets is x * $8.
Since Cindy spent her entire winnings of $50, we can write the equation:
y * $10 + x * $8 = $50
To find a viable solution, we can substitute different values for y and x until we find a combination that satisfies the equation. Here are a few possible solutions:
1. y = 3, x = 2
In this case, 3 robotics kits cost $30 (3 * $10), and 2 chemistry sets cost $16 (2 * $8). The total cost is $30 + $16 = $46.
2. y = 1, x = 5
In this case, 1 robotics kit costs $10 (1 * $10), and 5 chemistry sets cost $40 (5 * $8). The total cost is $10 + $40 = $50.
3. y = 2, x = 4
In this case, 2 robotics kits cost $20 (2 * $10), and 4 chemistry sets cost $32 (4 * $8). The total cost is $20 + $32 = $52, which exceeds Cindy's winnings of $50, so it is not a viable solution.
Therefore, a viable solution is y = 1 (1 robotics kit) and x = 5 (5 chemistry sets). Cindy can purchase 1 robotics kit and 5 chemistry sets using her entire winnings.
Cindy won 50.00 for getting first place in the science fair. She spent her winnings on robotics kits and chemistry sets. Each robotics kit y costs 10.00, while each chemistry set cost 8.00 x. Which of the following is a viable solution to the number of robotics kits and chemistry sets Cindy can purchase, assuming she spends her entire winnings?
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1 answer