To determine if the solutions are viable, we can set up the equation based on Cindy's total budget:
Let:
- \( y \) = number of robotics kits
- \( x \) = number of chemistry sets
The equation based on the total spent is: \[ 10y + 8x = 50 \]
Now, we can check each of the provided options to see if they satisfy this equation.
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For \((-5, 9)\): \[ 10(-5) + 8(9) = -50 + 72 = 22 \quad (\text{Not valid}) \]
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For \((5, 1)\): \[ 10(5) + 8(1) = 50 + 8 = 58 \quad (\text{Not valid}) \]
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For \((3, 2.6)\): \[ 10(3) + 8(2.6) = 30 + 20.8 = 50.8 \quad (\text{Not valid}) \]
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For \((0, 5)\): \[ 10(0) + 8(5) = 0 + 40 = 40 \quad (\text{Not valid}) \]
Therefore, none of the provided options are viable solutions for the number of robotics kits and chemistry sets Cindy can purchase while spending her entire $50.