To find the equations equivalent to \(4x + y = 3\), we can manipulate this original equation into different forms that maintain its equivalence.
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The first option is \(y = -4x + 3\). This is solving for \(y\) in terms of \(x\) and is indeed equivalent to the original equation.
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The second option is \(x + 4y = 3\). To check if this is equivalent, we can manipulate it:
- Start with \(x + 4y = 3\).
- Rearranging gives \(4y = 3 - x\), or \(y = \frac{3 - x}{4}\).
- To compare, we can try to express \(4x + y = 3\) in a similar form, or substitute this \(y\) back into \(4x + y = 3\) and see if we get a contradiction or equality.
When we multiply both sides of \(4x + y = 3\) by something to compare, we can find out equivalency.
Let’s try the other options:
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For the third option, \(8x + 2y = 6\):
- Divide the entire equation by 2 gives \(4x + y = 3\), which is equivalent.
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The last option is \(3x + y = 4\). To check equivalency:
- Rearranging gives \(y = 4 - 3x\). There’s no way from \(4x + y = 3\) to convert directly into \(3x + y = 4\), so they are not equivalent.
Thus, the two equations equivalent to \(4x + y = 3\) are:
- \(y = -4x + 3\)
- \(8x + 2y = 6\)