Choose the inequality that matches this situation.

Company A charges a fee of $25 plus $0.20 per brouchure to print and deliver them. Company B charges $0.30 per brochure. How many would need to be ordered for Company A to cost more than Company B?

\$0.20b+\$ 0.3b > 25b

\$0.20b+\$ 0.3b < 25b

\$25+\$ 0.2b >\$0.30b

\$25+\$ 0.2b <\$0.30b

1 answer

To determine when Company A charges more than Company B, we need to set up the cost equations for both companies.

  • The cost for Company A is \( C_A = 25 + 0.20b \) where \( b \) is the number of brochures.
  • The cost for Company B is \( C_B = 0.30b \).

We want to find the inequality for when Company A's cost exceeds Company B's cost:

\[ 25 + 0.20b > 0.30b \]

This means the correct inequality that matches the situation is:

\[ $25 + $0.20b > $0.30b \]