Choose the inequality that matches this situation. Company A charges a fee of $25 plus $0.20 per brouchure to print and deliver them. Company B charges $0.30 per brochure. How many would need to be ordered for Company A to cost more than Company B?

$0.20b + $0.30b > 25b
$0.20b + $0.30b < 25b
$25 + $0.20b > $0.30b
$25 + $0.20b < $0.30b

1 answer

To determine the inequality that matches the situation, we can define \( b \) as the number of brochures ordered.

  • Company A's cost: \( 25 + 0.20b \) (this includes a fixed fee of $25 plus $0.20 for each brochure)
  • Company B's cost: \( 0.30b \) (this charges $0.30 for each brochure with no fixed fee)

We want to find out when Company A's cost is greater than Company B's cost:

\[ 25 + 0.20b > 0.30b \]

This inequality states that the total cost from Company A is greater than that of Company B.

Thus, the correct inequality is:

\[ 25 + 0.20b > 0.30b \]

So, the answer is:

$25 + $0.20b > $0.30b