To determine how many different selections of four people can be made from a group of eight, we can use the combination formula. The formula for combinations is given by:
\[ C(n, r) = \frac{n!}{r!(n-r)!} \]
where:
- \( n \) is the total number of items (in this case, 8),
- \( r \) is the number of items to choose (in this case, 4), and
- \( ! \) denotes factorial, the product of all positive integers up to that number.
For Cherese's situation:
\[ C(8, 4) = \frac{8!}{4!(8-4)!} = \frac{8!}{4! \cdot 4!} \]
Now we can break it down step by step:
-
Calculate \( 8! \):
- \( 8! = 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 \)
-
Calculate \( 4! \):
- \( 4! = 4 \times 3 \times 2 \times 1 = 24 \)
-
Substitute into the combinations formula: \[ C(8, 4) = \frac{8 \times 7 \times 6 \times 5}{4 \times 3 \times 2 \times 1} \]
-
Perform the calculations:
- The numerator is \( 8 \times 7 = 56 \)
- Then \( 56 \times 6 = 336 \)
- And \( 336 \times 5 = 1680 \)
The denominator is \( 4! = 24 \).
-
Now divide the numerator by the denominator: \[ \frac{1680}{24} = 70 \]
Thus, the number of different selections of four people out of eight is:
\[ \boxed{70} \]