Checking to see if I did this right?

Titration of HN03 titrated with NaOH
ending result is 1.38.

Titration A, endpoint pH = 8 is pKa or pKb= 1.38x106=5.861 and

Titration of NH03 titrated with KOH ending results 1.54.

Titration B, endpoint pH = 7 is KaorKb=
Ka=1.54x105

1 answer

Beats me. I don't know what you're describing.