Hmm, let me see.
f(-2)=0, check
f(1)=0, check
f(2)=0, check
when expanded, the leading coefficient is 2
(polynomial=2x³-2x²-8x+8)
This checks too.
Yes, your answer is correct.
Check my answer please? Not sure if I did this right.
Let y = f(x) be a cubic polynomial with leading coefficient a = 2 and f(-2) = f(1) = f(2) = 0. find the factored form of f.
I got: f(x) = 2(x + 2)(x - 1)(x - 2)
1 answer