Chase and his children went into a restaurant where they sell drinks for $2 each and tacos for $3.50 each. Chase has $50 to spend and must buy at least 16 drinks and tacos altogether. If Chase decided to buy 6 tacos, determine all possible values for the number of drinks that he could buy.

Answer 1

Let's denote the number of drinks Chase buys as x.

The total cost of 6 tacos is $3.50 * 6 = $21.

Chase has $50 to spend, so he has $50 - $21 = $29 remaining to spend on drinks.

Since Chase must buy at least 16 drinks and tacos altogether, we have the inequality: x + 6 >= 16.
This simplifies to x >= 10.

To find possible values of x, we first need to find the maximum number of drinks he could buy with $29.
Each drink costs $2, so the maximum number of drinks he can buy is $29 / $2 = 14.5.
But since the number of drinks must be an integer, he can buy a maximum of 14 drinks.

Therefore, the possible values for x are: 10, 11, 12, 13, or 14.

So, Chase can buy 10, 11, 12, 13, or 14 drinks if he decides to buy 6 tacos.