Carter measures a line to be 5.8 cm long. If the actual measurement is 6 cm, find Carter's relative error to the nearest hundredth

1 answer

To calculate Carter's relative error, we use the formula for relative error:

\[ \text{Relative Error} = \frac{|\text{Measured Value} - \text{Actual Value}|}{\text{Actual Value}} \]

Where:

  • Measured Value = 5.8 cm
  • Actual Value = 6 cm

First, we find the absolute error:

\[ |\text{Measured Value} - \text{Actual Value}| = |5.8 - 6| = | -0.2 | = 0.2 \]

Next, we substitute this into the formula for relative error:

\[ \text{Relative Error} = \frac{0.2}{6} \]

Calculating this gives:

\[ \text{Relative Error} = \frac{0.2}{6} \approx 0.0333\ldots \]

To express this as a percentage, we multiply by 100:

\[ \text{Relative Error as Percentage} \approx 0.0333 \times 100 \approx 3.33% \]

Finally, rounding to the nearest hundredth, we find:

\[ \text{Relative Error} \approx 0.03 \text{ (as a decimal)}, \quad \text{or} \quad 3.33% \text{ (as a percentage)} \]

Thus, Carter's relative error is approximately 0.03 (or 3.33%).

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