Carter measures a line to be 9.3 cm long. If the actual measurement is 9 cm, find Carter's relative error to the nearest hundredth.

1 answer

To find Carter's relative error, we can use the formula for relative error:

\[ \text{Relative Error} = \frac{|\text{Measured Value} - \text{Actual Value}|}{|\text{Actual Value}|} \]

In this case, the measured value is 9.3 cm and the actual value is 9 cm.

  1. Calculate the absolute error: \[ |\text{Measured Value} - \text{Actual Value}| = |9.3 - 9| = |0.3| = 0.3 \]

  2. Now, use the absolute error in the relative error formula: \[ \text{Relative Error} = \frac{0.3}{9} \]

  3. Perform the division: \[ \frac{0.3}{9} \approx 0.0333\ldots \]

  4. To express this relative error as a percentage, multiply by 100: \[ \text{Relative Error} \times 100 \approx 0.0333 \times 100 \approx 3.33% \]

  5. Finally, rounding to the nearest hundredth gives us: \[ \text{Relative Error} \approx 3.33% \]

Thus, Carter's relative error is approximately 3.33%.