So find the mean, and median values for each set : )
Remember.. the means is add them all up and divide by the number in the set.
While the median is arrange each set from smallest to biggest and find the middle piece of data : )
Carol asked a random sample of 10 seventh grade student athletes and 10 seventh grade students who are not athletes how much time, in minutes, they spend studying each weeknight. She recorded her results in the table.
103 62 21 100 140
65 124 45 86 114
101 135 122 43 110
62 31 80 67 126
Calculate the mean and median data values for the student athletes sample.
Calculate the mean and median data values for the not student athletes sample.
When comparing the two samples, what conclusions can you draw about which group spends more time studying each weeknight?
8 answers
STUDENT ATHLETES:
MEAN: 83
MEDIAN: 90
NOT STUDENT ATHLETES:
MEAN: 85
MEDIAN: 90
MEAN: 83
MEDIAN: 90
NOT STUDENT ATHLETES:
MEAN: 85
MEDIAN: 90
thanks my ###### ####### ##### ###### ;0
Is he correct?
Because I got STUDENT ATHLETES MEAN is 86 and the MEDIAN 93. The NON STUDENT ATHLETES MEDIAN is 90.5 and the MEAN 87.7
he is correct
not sure but i assume
The answer is a. mean=86 and median=93
b. mean=87.7 and median=90.5
c. The mean for non-athletes is 1.7 minutes greater than for the athletes and the median for athletes is 2.5 minutes greater than for the non-athletes. So, it is too close to draw a conclusion at this point.
REWORD IT!!
b. mean=87.7 and median=90.5
c. The mean for non-athletes is 1.7 minutes greater than for the athletes and the median for athletes is 2.5 minutes greater than for the non-athletes. So, it is too close to draw a conclusion at this point.
REWORD IT!!