.......CO + Cl2 ==> COCl2
I.....319...220......0
C......-x....-x......x
E...319-x...220-x....x
Substitute the E line into the Kp expression and solve for x, 319-x, and 220-x. Then add mols of each to find total mols.
XCO = nCO/total mols
XCl2 = nCl2/total mols
XCOCl2 = nCOCl2/total mols.
The problem only asked for XCOCl2 but all of them can be calculated easily after you have the first one.
Carbon monoxide and chlorine gas react to form phosgene:
CO(g)+Cl2(g)⇌COCl2(g) Kp = 3.10 at 700 K
If a reaction mixture initially contains 319torr of CO and 220torr of Cl2, what is the mole fraction of COCl2 when equilibrium is reached?
1 answer