car comes to a stop over distance of 30.0m after the driver applies brakes. If the car decelerates @ contant rate of 3.50m/s2, what was the car's origianl sped?

Answer 1

Vf^2=vi^2+2ad a=-3.5m/s^2, d=30, solve for vi

Answer 2

210

Answer 3

14.5

Answer 4

14.5