1b. q2 being negative, it will be attracted to the left and right, but on the right, the charge is bigger, and closer. Q2 is attracted to the right.
Force=kq2(q3/1.5^2 -q1/2^2)
1a. Find the two repulsive forces (F12, F23) and add them as vectors. They are in the opposite direction.
2. If it is attractive, q2 is a negative charge. Use coulombs equation f =k q2q1/r^2 to find q2
Can you please provide me a starting point for these two questions
Question One:
Three charges are located on the +x axis as follows: q1 = +26 µC at x = 0 m, q2 = +13 µC at x = +2.0 m, and q3 = +42 µC at x = +3.5 m.
(a) Find the electrostatic force (magnitude and direction) acting on q2.
_______ N
+x
-x
+y
-y
(b) Suppose q2 were -13 µC, rather than +13 µC. Without performing any further detailed calculations, specify the magnitude and direction of the force exerted on q2.
_______ N
-y
-x
+y
+x
Question Two:
In a vacuum, two particles have charges of q1 and q2, where q1 = +3.5 µC. They are separated by a distance of 0.25 m, and particle 1 experiences an attractive force of 2.3 N. What is q2 (magnitude and sign)?
______ C
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