Sure!
To convert equations into slope-intercept form (y = mx + b), we need to solve for y.
Let's start with the equation 2x + 3y = 7:
Rearranging the equation, we have:
3y = -2x + 7
Dividing both sides by 3, we get:
y = (-2/3)x + 7/3
Therefore, the equation 2x + 3y = 7 in slope-intercept form is y = (-2/3)x + 7/3.
Next, let's convert the equation 3x - 3y = 3 to slope-intercept form:
Rearranging the equation, we have:
-3y = -3x + 3
Dividing both sides by -3, we get:
y = x - 1
Therefore, the equation 3x - 3y = 3 in slope-intercept form is y = x - 1.
Can you convert 2x + 3y = 7 and 3x - 3y = 3 into slope intercept form?
5 answers
Can you do it to 2x + 3y = 5?
Certainly! To convert the equation 2x + 3y = 5 into slope-intercept form, we need to isolate y on one side of the equation.
Starting with the given equation:
2x + 3y = 5
Subtracting 2x from both sides, we have:
3y = -2x + 5
Next, we divide both sides by 3 to solve for y:
y = (-2/3)x + 5/3
Hence, the equation 2x + 3y = 5 in slope-intercept form is y = (-2/3)x + 5/3.
Starting with the given equation:
2x + 3y = 5
Subtracting 2x from both sides, we have:
3y = -2x + 5
Next, we divide both sides by 3 to solve for y:
y = (-2/3)x + 5/3
Hence, the equation 2x + 3y = 5 in slope-intercept form is y = (-2/3)x + 5/3.
Can you also do it to 2x + 4y = 9? Thanks!! I'm starting to really get it!
Of course! I'm glad to hear that you're understanding the process. Let's convert the equation 2x + 4y = 9 into slope-intercept form.
Starting with the given equation:
2x + 4y = 9
Subtracting 2x from both sides, we have:
4y = -2x + 9
Next, we divide both sides by 4 to solve for y:
y = (-1/2)x + 9/4
Therefore, the equation 2x + 4y = 9 in slope-intercept form is y = (-1/2)x + 9/4.
Starting with the given equation:
2x + 4y = 9
Subtracting 2x from both sides, we have:
4y = -2x + 9
Next, we divide both sides by 4 to solve for y:
y = (-1/2)x + 9/4
Therefore, the equation 2x + 4y = 9 in slope-intercept form is y = (-1/2)x + 9/4.