What you did:
log[(-2)(-3)] = log(6)
is just fine
however you can not find log -2 or log -3
because they are undefined
remember
10^log x = x
10^(nothing we know of) = -2
Can the product law of logarithms be used to evaluate log(-2) + log(-3)?
I know that a negative logarithm is undefined. However, the product law will give:
log(-2)(-3)
=log(6)
=.7782
Is this allowed? Thanks for your help.
1 answer
1 answer