Isn't there are identity
sin2x=1-2sin^2 x ?
can someone show me step by step how to evaluate the integral of 2(sinx)^2 dx
I just don't understand how to do it....
3 answers
I don't understand what you are saying. there is no sin2x in my equation i don't think
i have to evaluate the integral 2(sin^2x)
i have to evaluate the integral 2(sin^2x)
Try
sin(x)sin(y)=(1/2)(cos(x-y)-cos(x+y))
Put y=x and noting that cos(0)=1, you will have a simpler expression to integrate.
sin(x)sin(y)=(1/2)(cos(x-y)-cos(x+y))
Put y=x and noting that cos(0)=1, you will have a simpler expression to integrate.
3 answers