x-sqrtx-12=0
let sqrtx=u
u^2-u-12=0
(u-4)(u+3)=0
u=4 or sqrt x=4 or x=16
u=-3 or sqrtx=-4 or x=16
can someone show me how to solve an equation algerbracially
x=sqrtx+10+2
2 answers
sorry the equation should read x=sqrt(x+10)+2