Asked by Jim

Can someone please help with this problem?

A burnout test was performed to determine the volume fractions of constituents in a
glass/epoxy composite. The following observations were made:
Weight of empty crucible = 47.6504 g
Weight of the crucible and small piece of composite = 50.2417 g
Weight of the crucible and glass after burnout = 49.7576 g

(a)Calculate the weight and volume fractions of glass fiber and epoxy resin. Assume that the
densities of the fibers and the resin are 2.5 and 1.2 g/cm3 respectively.


(b) Can the burn out test be used for kevlar/epoxy composites? Explain.
Answered by drwls
a) The mass of glass in the sample is the remaining mass that does not burn, 49.7576 - 47.6504 = 2.1072 g
The total mass of sample before burnout was 50.2417 - 47.6504 = 2.5913 9
The difference of those numbers is the original resin content, 0.4841 g.
Divide those numbers by the respective densities to get the volumes, and the volume fractions.

b) This analysis method will not work for Kevlar/epoxy, because the Kevlar can be oxidized.
Answered by Jim
Thank you very much.
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