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can someone please help me solve this question? I tried so many times but I still could not get it... x + y = 7 2x - y = 5 its...Asked by kabdul
can someone please help me solve this question?
I tried so many times but I still could not get it...
x + y = 7
2x - y = 5
its supposed to start as
[1 1 | 7]
[2 -1 | 5].....
and the ans is supposed to be (4,3)
thanks in advance
much appreciated
I tried so many times but I still could not get it...
x + y = 7
2x - y = 5
its supposed to start as
[1 1 | 7]
[2 -1 | 5].....
and the ans is supposed to be (4,3)
thanks in advance
much appreciated
Answers
Answered by
Reiny
There are 3 basic rules you can use on your matrix
1. you can interchange any two rows
2. you can multiply any row by a non-zero number
3. you can add/subtract a multiple of any row to any other row and replace the row with that result.
the idea is to make your matrix look like
1 0 a
0 1 b
then x=a
y=b
so for
1 1 7
2 -1 5
I will leave row 1 alone
row 2: 2xrow1 - row2
1 1 7
0 3 9
leave row1 alone
row2: divide by 3
1 1 7
0 1 3
row1: row1 - row2
leave row2 alone
1 0 4
0 1 3
now what does that matrix represent ?
1x + 0y = 4 , so x = 4
0x + 1y = 3 , so y = 3
Editorial:
Personally I think solving equations by matrix becomes an exercise in arithmetic manipulation.
Especially for an easy pair of 2 equations in 2 variables solving them this way is rather silly.
By the time somebody has solved one of these systems by the matrix method, I could have solved 3 or 4 systems by the old fashioned elimination method or in this case by substitution.
1. you can interchange any two rows
2. you can multiply any row by a non-zero number
3. you can add/subtract a multiple of any row to any other row and replace the row with that result.
the idea is to make your matrix look like
1 0 a
0 1 b
then x=a
y=b
so for
1 1 7
2 -1 5
I will leave row 1 alone
row 2: 2xrow1 - row2
1 1 7
0 3 9
leave row1 alone
row2: divide by 3
1 1 7
0 1 3
row1: row1 - row2
leave row2 alone
1 0 4
0 1 3
now what does that matrix represent ?
1x + 0y = 4 , so x = 4
0x + 1y = 3 , so y = 3
Editorial:
Personally I think solving equations by matrix becomes an exercise in arithmetic manipulation.
Especially for an easy pair of 2 equations in 2 variables solving them this way is rather silly.
By the time somebody has solved one of these systems by the matrix method, I could have solved 3 or 4 systems by the old fashioned elimination method or in this case by substitution.
Answered by
Damon
Hey ah kabdul. I did two of these Gauss Jordan things for you last night and Reiny did one now. Are you getting it? Try one yourself please and let us see if you can do it.
I do not like the method much by hand, but for large systems of equations that need to be solved methodically by computer programming this is the way to go, or used to be. The Fortran and octal programs I used to write are now incorporated in any old scientific calculator.
I do not like the method much by hand, but for large systems of equations that need to be solved methodically by computer programming this is the way to go, or used to be. The Fortran and octal programs I used to write are now incorporated in any old scientific calculator.
Answered by
Reiny
Ahh, Fortran
How things have changed.
I recall studying under Wesley Graham
at the University of Waterloo back in 1962
when he started to tweak Fortran and came up with several improved version of it, eventually becoming WatFor and WatBol (for Waterloo Fortran and Waterloo Cobol)
If I rummage through my basement I might still find some boxes of computer cards punched out in those programs.
Many of Graham's students are now big-shots at RIM (Research in Motion or the Blackberry Company, based right here in Waterloo)
http://csg.uwaterloo.ca/~jwgraham/g+m/liveslived.htm
How things have changed.
I recall studying under Wesley Graham
at the University of Waterloo back in 1962
when he started to tweak Fortran and came up with several improved version of it, eventually becoming WatFor and WatBol (for Waterloo Fortran and Waterloo Cobol)
If I rummage through my basement I might still find some boxes of computer cards punched out in those programs.
Many of Graham's students are now big-shots at RIM (Research in Motion or the Blackberry Company, based right here in Waterloo)
http://csg.uwaterloo.ca/~jwgraham/g+m/liveslived.htm
Answered by
Damon
We used the Waterloo software at MIT in fact, same era.
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