according to my rough sketch the second course makes a 100º with the first course.
so by the cosine law
x^2 = 200^2 + 150^2 - 2(200)(150)cos 100º
solve for x
(I got 270.03, but check my arithmetic)
then by sine law, the angle opposite the 150 is
sin(theta)/150 = sin 100/270.03
I get theta = 33.16º
so the bearing of the resultant is
N73.16E
Can someone please help me. I don't get this question. Thank You
In order to avoid a severe storm at sea a ship is set to sail 200 km at an angle of N40*E, then 150 km at an angle of S60*E. What is the displacement of the ship?
1 answer
1 answer