Can someone please explain to me how to solve this:

Question

Simplify 6P2.
A) 30
B) 15
C) 12
D) 720

Answer 1

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Answer 2

Thanks!

Answer 3

You're welcome.

Answer 4

Lession 7 probability unit test

1. A

Answer 5

thanks lynn lmao

Answer 6

Simplify 6P2.
bot please help

Answer 7

To simplify 6P2, we use the permutation formula:

nPp = n!/(n-p)!

So, substituting 6 for n and 2 for p,

6P2 = 6!/(6-2)! = 6!/4! = (6*5*4!)/4! = 30

Therefore, the answer is A) 30.

Answer 8

Simplify 9C4.
bot please help

Answer 9

To simplify 9C4, we use the combination formula:

nCr = n!/(r!(n-r)!)

So, substituting 9 for n and 4 for r:

9C4 = 9!/(4!(9-4)!) = 9!/4!5! = (9*8*7*6*5!)/4!5!

Simplifying the factorials:

(9*8*7*6)/(4*3*2*1) = 126

Therefore, the answer is 126.

Answer 10

You and 5 friends go to a concert. In how many different ways can you sit in the assigned seats?
bot please help

Answer 11

The number of ways you and your 5 friends can sit in assigned seats is equal to the number of permutations of 6 objects, which is given by the formula:

nPp = n!/(n-p)!

Substituting 6 for n and 6 for p, we get:

6P6 = 6!/(6-6)! = 6!/0! = 6 x 5 x 4 x 3 x 2 x 1 = 720

Therefore, there are 720 different ways that you and your 5 friends can sit in the assigned seats.

Answer 12

You own 6 pairs of jeans and want to take 2 of them with you on vacation. In how many ways can you choose 2 pairs of jeans?
bot please help

Answer 13

The number of ways you can choose 2 pairs of jeans out of 6 is given by the formula for combinations. We can use the following formula to determine the number of ways to select r items from a set of n items:

nCr = n! / (r! * (n-r)!)

We want to select 2 pairs of jeans, so r = 2. We have n = 6 pairs of jeans to choose from. Substituting these values into the formula, we get:

6C2 = 6! / (2! * (6-2)!) = 15

Therefore, there are 15 different ways you can choose 2 pairs of jeans out of 6.