To make it easy to type let's call ethylene glycol just eth.
delta T = Kf*m
You know delta T (15.5) and you know Kf, solve for molality eth.
m = mols/kg solvent
You know m eth and kg solvent, solve for mols eth.
mols = grams/molar mass. You know mols eth and molar mass eth, solve for grams eth.
Can someone please explain this to me?!
Please! Thank you!
How much (in kilograms) ethylene glycol antifreeze (C2H6O2)(molar mass 62.02 g/mol) has to be added to 14.4 kg of water to get a mixture that freezes at -15.5 degrees C. For water Kf = 1.86 degrees C kg/mol
1 answer