same angular momentum
equal in magnitude but opposite in direction linear momentum
so 2 (2379) V
2379 V^2 / R = G * Mearth *2379 / R^2
so V^2 = G Mearth / R
where R = 10^5 + Rearth
Can someone help with this question please,
The Chandrayaan-2 orbiter is orbiting the moon in a circular polar orbit at a height of 1.00×105 m above the surface. It has a mass of 2379 kg. What is the change of momentum in the orbiter from when it passes over the North Pole compared to when it passes over the South Pole?
1 answer
1 answer