Can someone help with this question please,

The Chandrayaan-2 orbiter is orbiting the moon in a circular polar orbit at a height of 1.00×105 m above the surface. It has a mass of 2379 kg. What is the change of momentum in the orbiter from when it passes over the North Pole compared to when it passes over the South Pole?

1 answer

same angular momentum
equal in magnitude but opposite in direction linear momentum
so 2 (2379) V

2379 V^2 / R = G * Mearth *2379 / R^2
so V^2 = G Mearth / R
where R = 10^5 + Rearth
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