Square both sides:
2x^2 + 5x + 6 = x^2
x^2 + 5x + 6 = 0
(x+2)(x+3) = 0
x = -2 or x=-3
BUT, since we squared, all answers must be verified in the original equation
Neither works, so there is no solution.
had your equation been
√(2x2 - 5x + 6)]=x
the solution would have been
x = 2 or x=3 and both of those would have verified.
Can someone help me solve this equation?/
[SQRT(2x2 + 5x + 6)]=x
3 answers
Thank you.
Also can you show me how I would do this equation??
2[SQRT(x + 4)] = 3
Also can you show me how I would do this equation??
2[SQRT(x + 4)] = 3
same way
square both sides
4(x+4) = 9
4x+16 = 9
4x = -7
x = -7/4
when verifying it worked.
square both sides
4(x+4) = 9
4x+16 = 9
4x = -7
x = -7/4
when verifying it worked.
1 answer