Can someone help me on how to do this problem

2xy(3x^2)(4y^-1)(5z^-3)

4 answers

What is the power of y? Is it 2? Are you supposed to multiply it all out?

It is not clear what the "problem" is. You cannot solve for x, y and z with one equation. In fact, you have not even written an equation.

You have already done a lot of factoring, but 4y^2 -1 and 5z^3 -3 can be factored some more.
well it says to simplify.and that's all it gives me.
its either one of the following answers
a.6x^3/20z^3
b.6x^3y^2/20z^2
c.120x^3/z^3
d.120x^3z^3
its (c), 120x^3/z^3.
thank you.
how did you get the answer?