1. N2 + 3H2 ==> 2NH3 (balanced equation)
Now put the RAM (relative atomic masses) to each reactant.
2*14 + 3*2 ==> 2*(17)
28 + 6 ==> 34
Therefore 28 grams of N2 with 6 grams of H2 will yield 34 grams of NH3 (assuming one of the reactants will be exhausted).
2.
Since only 6 grams of H2 out of 25 grams has been used for the reaction, what would be the quantity left?
Can someone check my first answer and help me with the second question? Thanks so much!! :D
1. N2 + 3H2 ==> 2NH3 : How many grams of NH3 can be produced from the reaction of 28 g of N2 and 25 g of H2?
==> I got 37.5 grams.
2. How much of the excess reagent in Problem 1 is left over?
==> I really have no idea how to do this. Can someone please explain this to me? Thanks!
1 answer