Asked by Mike

Can somebody help with these.
Simplify (be sure to rationalize all denominators)
11. 3/[SQRT(5) - 2]
and
this..
Note: I only need help on the b part of the question..
15. Assume that a surveyor stands at the top of a mountain that is “h” feet tall. If the distance (in feet) that he can see is defined by d = 3200.2 SQRT(h), then answer the following. (a) How far can the surveyor see from the top of a 2000-foot mountain? (b) How tall is the mountain, if the surveyor can see 15 miles? (Note: 1 mile equals 5280 feet.)
Answered by drwls
11. Multiply numerator and denominator by sqrt(5) + 2. The denominator will become 5 - 4 = 1.

15. Use the formula you were given to solve for h, where d = 15x5280 = 79,200 feet
Answered by Mike
is that the answer for number 11?

and would the distance equal 79,200? and if so would I convert back to miles?

Thank you.
Answered by drwls
You have not completed #11. On #5, I gave you the distance in feet (79200). You solve for the altitude. We are here to help you, not to provide complete solutions for you to turn in
Answered by Mike
Ok yes i do ont want the answers but I want to know the next step in solving the equation....
once i have 5-4=1 as my dementaor what would i do?
Answered by drwls
Denominators of 1 can be ignored.
x/1 = x, no matter what x is
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