[(8.99*10^9)*(5.55*10^-6C)*(16.33*10^-6C)]/10
8.99 * 5.55 * 1.633 * 10^-3
81.47 * 10^-3
= .0815
but what is this nonsense? /=(√10)^2=
is that 10 maybe in millimeters or centimeters or something? What is this problem about?
Can somebody explain how [(8.99*10^9)*(5.55-µC)*(16.33 µC)]/=(√10)^2=815.66?
I got [(8.99*10^9)*(5.55*10^-6C)*(16.33*10^-6C)]/10=.08156835
8 answers
I think my teacher write it in centimeter.
Then CHANGE IT TO METERS !!!!!
I did. it give me 8.156835 not the 815.66
if this is k Q1 Q2 /d^2
use d in meters
use d in meters
what was d in centimeters?
what did you use for d in meters?
You have a typo so I have no idea what you did.
/=(√10)^2
what is = sign?
where is sqrt come from?
what did you use for d in meters?
You have a typo so I have no idea what you did.
/=(√10)^2
what is = sign?
where is sqrt come from?
Teacher[(8.99*10^9)*(5.55-µC)*(16.33 µC)]/(√10cm)^2=815.66N/C
Is this right?
My[(8.99*10^9)*(5.55-µC)*(16.33 µC)]/(√.10m)^2=8.1568N/C
Is this right?
My[(8.99*10^9)*(5.55-µC)*(16.33 µC)]/(√.10m)^2=8.1568N/C
I guess your charges are at a distance of √10cm
apart. that is d = √.1 meter
then d^2 = 0.1 meter
k Q1 Q2 /d^2 = [(8.99*10^9)*(5.55*10^-6 C)*(16.33*10^-6 C)] /0.1
= 814.7 * 10^-3 / 10^-1 = 814.7 * 10^-2 = 8.147 N (not N/C)
I agree with you
apart. that is d = √.1 meter
then d^2 = 0.1 meter
k Q1 Q2 /d^2 = [(8.99*10^9)*(5.55*10^-6 C)*(16.33*10^-6 C)] /0.1
= 814.7 * 10^-3 / 10^-1 = 814.7 * 10^-2 = 8.147 N (not N/C)
I agree with you