Compute the charge Q associated the V = 540 V voltage difference using the formula
Q = C V
Then divide Q by the electron charge (1.6*10^-19 C) to get the number of electrons transferred.
Can please help me understand this question?
A capacitor has a capacitance of 2.0 10-8 F. In the charging process, electrons are removed from one plate and placed on the other plate. When the potential difference between the plates is 540 V, how many electrons have been transferred?
________electrons
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