Can anyone explain how to use the chain rule and power rule together to find the first derivative and please do these examples.

f(x) = -3x^4/(sqrt(4x-8))

g(x) = ((2x+5)/(6-x^2)^4

g(x) = (8x^3)(4x^2+2x-3)^5

y = [1/(4x+x^2)^3]^3

Thank you so much!

1 answer

I will give you the 'first-line' derivatives of the first two questions

a) f'(x) = [(4x-8)^(1/2)(-12x^3) - (-3x^4)(1/2(4x-8)^(-1/2)(4)]/(4x-8)
= ....

b) I see you had a double bracket at the front, but one bracket is not closed.
Did you mean [(2x+5)/(6-x^2)]^4 ?

c) g(x) = (8x^3)(4x^2+2x-3)^5
g'(x) = 5(4x^2+2x-3)^5(8x+2)(8x^3) + 24x^2(4x^2+2x-3)^5
= ....

d) y = [1/(4x+x^2)^3]^3
y = (4x+x^2)^-9
y' = -9(4x + x^2)^-10(4+2x)
= ....
Similar Questions
  1. How do I use the chain rule to find the derivative ofsquare root(1-x^2) also, are there any general hints or tips for
    1. answers icon 1 answer
  2. Find the indefinite integral in two ways.∫(2x-1)^2 dx The first way I used was using the power rule and chain rule with
    1. answers icon 1 answer
  3. Find the derivative of [(2+x)/(x-3)]^(2/5)I tried the power of a function rule, quotient rule, the chain rule but keep getting
    1. answers icon 2 answers
    1. answers icon 1 answer
more similar questions