you have an isosceles triangle with two sides of length 2, and the included angle is π/6
so the area is 1/2 * 2*2 * sin π/6 = 1
Can anybody help me please? i dont get it :(
Two points on the polar plane are given as p1 = (−2,3π/2 ) and p2 = (2,2π/3). Please find the triangular area formed by P1, P2, and the pole.
3 answers
how can I find the included angle?
Thank you so much