To determine which graph accurately displays the situation after Callie invests her $1,000 scholarship at a 9% interest rate compounded annually, we can analyze the situation using the formula provided:
\[ a(t) = 1,000(1.09)^t \]
Here, \( a(t) \) is the amount in the account after \( t \) years. Since Callie uses the scholarship 10 years later, we must evaluate the function at \( t = 10 \):
\[ a(10) = 1,000(1.09)^{10} \]
Calculating \( (1.09)^{10} \):
\[ (1.09)^{10} \approx 2.36736 \]
Now plugging it back into the equation:
\[ a(10) \approx 1,000 \times 2.36736 \approx 2367.36 \]
This means that after 10 years, the amount in the account is approximately $2367.36.
Now we analyze the graph options provided:
- First Graph: X-axis ranges from 0 to 5 and Y-axis from 0 to 2000. This doesn't cover 10 years or amounts over $2000.
- Second Graph: X-axis from 0 to 14 and Y-axis from 0 to 3,500. This can cover up to 10 years and amounts over $2000.
- Third Graph: X-axis from 0 to 10 and Y-axis from 0 to 2000. This does not reach the approximately $2367.36 amount.
- Fourth Graph: A decreasing curve, which does not represent our situation of growing savings with compounded interest.
Given this analysis, the second graph accurately displays the situation, as it covers both a sufficient range for years (up to 14) and amounts (up to 3,500), which includes the approximated value of $2367.36 after 10 years.
The correct response is the second graph.