In a contest in which 8 contestants are entered, in how many ways can the 5 distinct prizes be awarded?

Answer 1

permutations:
nPr = n(n - 1)(n - 2) ... (n - r + 1) = n! / (n - r)!

Answer 2

n = 8

r = 5

nPr = 8!/(8-5)! = ?

8! = "8 factorial" = 8 * 7 * 6* 5 * 4 * 3 * 2 * 1

I hope this helps a little more.

Answer 3

6720