To analyze Callie's investment of $1,000 at a 9% interest rate compounded annually, we can look at the formula provided:
\[ a(t) = 1000(1.09)^t \]
This is an exponential growth function where \( a(t) \) is the amount in the account after \( t \) years.
Let's determine what happens after 10 years:
\[ a(10) = 1000(1.09)^{10} \]
Calculating \( (1.09)^{10} \):
\[ (1.09)^{10} \approx 2.36736 \]
Now, let's calculate the amount:
\[ a(10) \approx 1000 \times 2.36736 \approx 2367.36 \]
After 10 years, the amount in the account will be approximately $2,367.36.
Now, we evaluate which graph fits this situation.
- The graph must show an increasing curve because the amount in the account grows over time.
- The amount at \( t = 10 \) years must be around $2,367, which means we need to look for a graph where the y-coordinate at \( x = 10 \) is close to but below $2,500.
- The x-axis ranges must accommodate at least up to 10 years.
Let's analyze the options:
- The first graph has the x-axis ranging from 0 to 10 and the y-axis from 0 to 2,000. The maximum height is too low as it does not reach 2,367.
- The second graph looks to range from 0 to 14 on the x-axis and 0 to 3,500 on the y-axis, which likely allows for the required values since it can cover up to 2,367.
- The third graph shows a decreasing curve, which is not applicable here as the amount is increasing.
- The fourth graph has the x-axis from 0 to 5, which is not sufficient to cover 10 years.
From this analysis, the second graph, which depicts an increasing curve covering a more extensive time scale and giving a higher range on the y-axis, is the accurate representation of Callie's investment situation.