Calculate the volume occupied by 5.25 g of nitrogen at 26*c [temperature] and 74.2 cm of pressure.?
4 answers
PV = nRT
PV=nrT
V= nrT/ P
n = 5.25/14 (mass of nitrogen)
= 0.375
R = 0.0821
T = 27+273 = 299
P = 74.2 cm x 10 = 742mm of pressure
V=nRT/P
ANS=> 0.012 dm3
V= nrT/ P
n = 5.25/14 (mass of nitrogen)
= 0.375
R = 0.0821
T = 27+273 = 299
P = 74.2 cm x 10 = 742mm of pressure
V=nRT/P
ANS=> 0.012 dm3
ChuLbuLi has erred.
mass N is 14. mass N2 is 28; therefore,
n = 5.25/28 = ?
P must be in atmosphere if you use R as 0.08206 L*atm/mol*K.
P = 74.6 cm/76.0 cm = ? atm.
mass N is 14. mass N2 is 28; therefore,
n = 5.25/28 = ?
P must be in atmosphere if you use R as 0.08206 L*atm/mol*K.
P = 74.6 cm/76.0 cm = ? atm.
This answer wrong . And stop making fool of students , if you don't know anything . The correct answer is 4.71 litres
Kapil Saini , IITian (IIT Bombay)
Kapil Saini , IITian (IIT Bombay)
2 answers