1.Calculate the volume occupied by 3.2g of oxygen at 300K and 100KNm^-2.(R=8.3J/mol/K,Oxygen =16).

Question

2.Calculate the volume occupied by 0.125mol of Oxygen at 27°C and a pressure of 2.02×10^5Nm^2.(1mole of gas occupies 22.4dm^3 at Standard temperature and pressure,where standard temperature is =1.01×10^5Nm^-2)

Answer 1

1. 100 kN/m^2 = 0.998 atm, R = 0.08206 L*atm/mol*K , n = 3.2/32
PV = nRT
0.998*V = (3.2/32)*0.08206 L*atm/mol*K * 300 K
Solve for V in liters

For 2. You surely don't mean standard temperature is =1.01×10^5Nm^-2)

Answer 2

Can someone solve number 2 question please